大智慧横盘放量突破源码大智慧公式
2017-07-05 来源：网络 编辑：翔博软件
LAST((H-L)/REF(C,1)0.1) AND VOLREF(VOL,1)*2 AND CREF(C,1)*1.03 AND DMI.PDIDMI.MDI AND CROSS(DMI.ADX,DMI.ADXR) ANDDMI.ADXRDMI.MDI AND DMI.PDIDMI.ADX ANDKDJ.DREF( KDJ
LAST((H-L)/REF(C,1)<0.1) AND VOL>REF(VOL,1)*2 AND C>REF(C,1)*1.03
AND "DMI.PDI">"DMI.MDI" AND CROSS("DMI.ADX","DMI.ADXR")
AND"DMI.ADXR">"DMI.MDI" AND "DMI.PDI">"DMI.ADX" AND"KDJ.D">REF("KDJ.D",1);
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